Russian puzzle club 'Diogen'
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Championship of Diogen club 2007

 
Answers must be sent not later then 2007 October 31 to address olgainna@rambler.ru


1. Phrase of year 2007 

Write an arithmetic expression which value equal to 2007 using Russian name of
A. digits
1 - ÎÄÈÍ2 - ÄÂÀ3 - ÒÐÈ
4 - ×ÅÒÛÐÅ5 - ÏßÒÜ6 - ØÅÑÒÜ
7- ÑÅÌÜ8 - ÂÎÑÅÌÜ9 - ÄÅÂßÒÜ

B. and arithmetic signs:
+ - ÏËÞÑ- - ÌÈÍÓÑ
* - ÓÌÍÎÆÈÒÜ ÍÀ/ - ÄÅËÈÒÜ ÍÀ


Arithmetic operations are applied in order from left to right. You cannot use brackets.
Example (using the number 10 - ÄÅÑßÒÜ):
ÄÅÑßÒÜ ÓÌÍÎÆÈÒÜ ÍÀ ÄÅÑßÒÜ, ÓÌÍÎÆÈÒÜ ÍÀ ÄÅÑßÒÜ, ÓÌÍÎÆÈÒÜ ÍÀ ÄÂÀ, ÏËÞÑ ÑÅÌÜ
(In digits this means 10õ10õ10õ2+7). This expression uses 62 letters (12 words).
Try to use the minimum possible number of letters.

Score: 50 points for the best solution, 45 - for the second best and so on.


2. Pentadividing. 

Black out 4 squares in the 8x8 grid. Then draw some (may be none) cell borders so that obtained grid can be divided into full pentamino set in exactly one way. Drawn borders are used as pentamino borders.
Minimize the quantity of drawn borders. Example: 12 borders.
Illustration for puzzle 2


Score: 50 points for the best solution, 45 - for the second best and so on.

3. Square with polygons. 
Divide a 5õ5 square to non-congruent polygons. All vertices should be at the grid nodes.
Try to obtain maximum quantity of polygons.
Example: 2õ2 square divided to four non-congruent polygons

Score: 50 points for the best solution, 45 - for the second best and so on.
Illustration for puzzle 3

Rolled blocks 1x2x3.(author - Vasiliy Ilukhin) 
6 blocks 1x2x3 stay on the board 5x6. You can roll up them over the edges. Using minimum numbers of rolls move the blocks from position A to position B (see the picture). Use block's digits and first letter of direction (left, right, up, down) to note you moves. Possible start is: 5drr, 6drr, 3d, 4d, 2lld.

Score: 50 points for the best solution, 45 - for the second best and so on.
Illustration for puzzle 4
Olga Lentieva

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